"""
344. 反转字符串
简单
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提示
编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 s 的形式给出。

不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。



示例 1：

输入：s = ["h","e","l","l","o"]
输出：["o","l","l","e","h"]
示例 2：

输入：s = ["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]


提示：

1 <= s.length <= 105
s[i] 都是 ASCII 码表中的可打印字符
"""
from typing import List


class Solution:
    def reverseString(self, s: List[str]) -> None:
        """
        Do not return anything, modify s in-place instead.
        """
        temp=''
        # len(s)/2 得一个浮点数，range里不能为浮点数 所以用//，//为整数除法
        for i in range(len(s)//2):
            temp = s[i]
            s[i] = s[-1-i]
            s[-1-i] = temp
        print(s)
if __name__ == '__main__':
    Solution().reverseString(["h","e","l","l","o"])

